Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
$(a) \frac{1}{8} E \quad\quad (b) \frac{1}{4} E (c) \frac{1}{2} E \quad\quad (d) \frac{2}{3} E$
Text Solution
Verified by ExpertsThe correct answer is:
B
$\frac{U}{E} = \frac{\frac{1}{2} m \omega^{2} y^{2}}{\frac{1}{2} m \omega^{2} a^{2}} = \frac{y^{2}}{a^{2}} = \frac{\left(\frac{a}{2}\right)^{2}}{a^{2}} = \frac{1}{4} \Rightarrow U = \frac{E}{4}$
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